BetterPHP

Posted: **Fri Oct 28, 2011 3:07 am**

Why does this code works fine in winows and not in Linux,it should display a number of thumbnails
which it does in windows, but in Linux it only shows 1 thumbnail ? The print_r displays the right
number of entries.

$images = "thumbs/$name/";

$big    = "gallery/$name/";



if($handle=opendir($images)) {

	while(false!==($file=readdir($handle))) {

	  if($file !=="."&&$file !=".."&&$file !=rtrim($big,"/")) {

	    $files[]=$file;

       }

    }

  closedir($handle);

 }

//print_r($files); 



echo'<table width="100%" cellspacing="3"><tr>';



$cols = 6;

$colCtr = 0;



       foreach($files as $file) {

	 if($colCtr % $cols == 0){ 

	   echo'</tr><tr><td colspan="6"><hr/></td></tr><tr>';

	   echo'<td align="left"><a href="gallery/'.$name.'/'.$file.'"><img src="thumbs/'.$name.'/'.$file.'"/></a></td>';

        $colCtr++;

  }

}

echo'</table>';

?>

Posted: **Fri Oct 28, 2011 5:57 pm**

It might be that the path is wrong, if you view the source of the generated page does the HTML look like it should ? Also you may want to look into using the scandir or glob functions since your method is fine, but a bit php4.

Posted: **Thu Nov 03, 2011 12:46 am**

Hi Jacek

I have tried your suggestions and have'nt been able to fix my problem, so i looked in other places.
I removed the if statement

if($colCtr % $cols == 0){

this allows the images to be diisplayed but in a list view, which is not what i want. There is nothing wrong with the if
statement, so why does linux display one image then stop, 2 mod 6 == o therefore
it should not stop. Is there a fault with my logic or does the problem lie some where else, maybe the html code.

As usual thank you for your help

Posted: **Thu Nov 03, 2011 5:39 pm**

Well the problem is not with the OS, so what else is changing ?

Are you using the same browser to view the page both times ?

The HTML you are using is not the best, so a good start might be to look at the source of the page to see what is being ouput and make sure it is valid.

I would write what you are trying to do like this, taking a slightly different approach.

<?php

$files = scandir($images);
unset($files[0], $files[1]);

$rows = array_chunk($files, 6);

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
	<head>
		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
		<style type="text/css">
			a, img {
				float:	left;
				border:	none;
			}
		</style>
		<title>My Gallery !</title>
	</head>
	<body>
		<?php
		
		foreach ($rows as $row){
			echo '<div>';
			
			foreach ($row as $image){
				echo '<a href="gallery/', $name, '/', $image, '"><img src="thumbs/', $name, '/', $image, '" /></a>';
			}
			
			echo '</div>';
		}
		
		?>
	</body>
</html>

The array_chunk() splits the list of files up into blocks of 6.

Posted: **Sat Nov 05, 2011 12:07 am**

Thanks Jacek
Your code works really well.

Iwould really like to display the names of the images aswell, I am considering
using the exif function to get the names,what do you think or what would you suggest.
Is there a better way, hopefully eaiser.

Thank you

Posted: **Sat Nov 05, 2011 7:51 pm**

You should have the names already, in the $image variable. Can you just use that ?

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