To be a function or not to be a function.
Posted: Sun Aug 28, 2011 9:49 pm
Hello All.
I just checked out some nice code on http://www.php.net/manual/en/function.m ... -assoc.php
This is the code, now my problem is I like to make this in to a function. I did change the code some to make variables for me so I can each them out on a other site. The problem is, when I make it into a function I lose the variables outside of the function.
I need to make this in to a function because I need to gather much more information from a total of 5 databases. ( I would like to use this function 5 times to create variables I can use later on a other page.
while ($row = mysql_fetch_assoc($result)) {
extract($row, EXTR_PREFIX_SAME, "info");
}
echo "This is my new variable from the database:" . " " . $example ."<br/>";
I also like to say that I know its not a easy one and don´t expect you all to know how to fix this problem, however if there is one that know how please let show me a example on how the function would look like.
best regards
Wizzuriz...
I just checked out some nice code on http://www.php.net/manual/en/function.m ... -assoc.php
This is the code, now my problem is I like to make this in to a function. I did change the code some to make variables for me so I can each them out on a other site. The problem is, when I make it into a function I lose the variables outside of the function.
I need to make this in to a function because I need to gather much more information from a total of 5 databases. ( I would like to use this function 5 times to create variables I can use later on a other page.
while ($row = mysql_fetch_assoc($result)) {
extract($row, EXTR_PREFIX_SAME, "info");
}
echo "This is my new variable from the database:" . " " . $example ."<br/>";
<?php $conn = mysql_connect("localhost", "mysql_user", "mysql_password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("mydbname")) { echo "Unable to select mydbname: " . mysql_error(); exit; } $sql = "SELECT id as userid, fullname, userstatus FROM sometable WHERE userstatus = 1"; $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } // While a row of data exists, put that row in $row as an associative array // Note: If you're expecting just one row, no need to use a loop // Note: If you put extract($row); inside the following loop, you'll // then create $userid, $fullname, and $userstatus while ($row = mysql_fetch_assoc($result)) { echo $row["userid"]; echo $row["fullname"]; echo $row["userstatus"]; } mysql_free_result($result); ?>If you know how this can work please let me know.
I also like to say that I know its not a easy one and don´t expect you all to know how to fix this problem, however if there is one that know how please let show me a example on how the function would look like.
best regards
Wizzuriz...