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content won't display

Posted: Sat Feb 09, 2013 3:46 pm
by Porkypie
Hey!

I made this "while loop", but the content that comes after my loops won't display anymore.

Can anyone tell me why? here's the code:

[syntax=php] <?php

$result = mysql_query("SELECT `gebruikers_naam`, `achternaam`, `voornaam`, `email`, `telefoon` FROM gebruikers");
echo mysql_error();
echo "<table>
<tr>
<th style='display:none;'>id</th>
<th>Gebruikersnaam</th>
<th>voornaam</th>
<th>achternaam</th>
<th>E-mail</th>
<th>telefoon</th>
<th>wijzigen</th>
<th>Verwijderen</th>
</tr>";


while ($row = mysql_fetch_array($result)){

echo "<tr>";
echo "<td style='display:none;'>" . $row['id'] . "</td>";
echo "<td>" . $row['gebruikers_naam'] . "</td>";
echo "<td>" . $row['voornaam'] . "</td>";
echo "<td>" . $row['achternaam'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['telefoon'] . "</td>";
echo "<td> wijzig </td>";
echo "<td> <input type='button' name='verwijderen' value='verwijder' /> </td>";
echo "</tr>";
}
echo "</table>";

die();
?> [/syntax]

Re: content won't display

Posted: Mon Feb 11, 2013 1:06 pm
by ExtremeGaming
Well anything after the loop is being cancelled by your call of die(); which ends the entire script.