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i successfully create the login for guest but i had one problem now the welcome session i get Undefined variable: user_data how can i define the variable in function any idea ? or can i echo username data and if its not found i do else echo statement ? i do somthing lik this but i stell get undefien...

i make function to allow login for guest from login form but i have an error now the welcome session for guest i get Undefined variable any idea about how to defined it in welcome session this is the welcome session that i use it

welcome

<?php echo $user_data['username']; ?>

thanks for replay that not what i need i just need login form for guest and in the same time allow them to login .

Secret guest login o.O Explain the problem ? i just creat form for guest login and form for userlogin basicly user login needs name in data base to login what iam trying to do is allow the guest login form to also login but i have problem with welcome session :( like if i echo the session of regist...

Djmann1013 wrote:I am still getting the error.

past the code after edit..

Djmann1013 wrote:How do I fix it?

while($row = mysql_fetch_assoc($result))

also you may use fetch_array

Fix this line

while(($row = mysql_fetch_assoc($result)) !== false) {

guys iam lost i cant make a secure guest login i would if we have tut about it

Thanks Bro for replay , let me explain more lets say i have visitor and he dont have registered account i want make him able to login as guest without registration and store his name session in database.

Hi guy's ,, i follow jacek tut and i finish the register and login and thank you very much jacek for every thing you do to teach us god bless you . i just now need help in somthing maybe easy for you guy's but its still hard to me i want add Guest login function and store it in database any idea abo...

hello guys , iam trying to protect some pages on my script, i want control on session who can show this page i make somthing but after i check i see that's works with 1 name only i want make it allow to many name here is example to be more clear $pro = $user_data['username']; if ($pro != "drama...

If you add echo mysql_error(); under the query that is failing, it usually tells you what's wrong. $total = mysql_query("SELECT COUNT (user_id) FROM `tbl_users` WHERE `username` = '{$user}' AND `password` = '{$pass}'"); echo mysql_error(); return (mysql_result($total, 0) == '1') ? true : ...

that is a very crucial piece of code that you need. If you don't have that, you won't show any errors that occur. Just fix the typo. It's spelled errors, not erros. Thxxxxxxxxxxxxxxxxx you got my errors Broo , but now one more problem i get this error in login.php and this is the user.inc.php conte...

jacek wrote:You misspelled errors on this line

if (empty($erros)===false){

That might be causing what ever the error is to be hidden ?

I remove that line

<?php
if (empty($erros) === false){
?>

and the problem is fixed ,, bit this will effect on security or somthing ?

but i still get the same problem nothing happend in page even it didnt show any errors just submit and i get the same page

Temor wrote:that error would probably be

password cannot be empty.

if(empty($_POST['password']) || empty($_POST['repeat_pasword'])){

You missed an S in repeat_password.

aww thanks you got me

thank you for replay, well i remove that line ?