BetterPHP

You can use a url rewrite in .htaccess I believe. Try adding this to your .htaccess Replace the two occurrences of file with your file name, excluding the extension (assuming it ends in .php, if not replace .php with .whatever) RewriteEngine On RewriteRule ^file\.php$ /file.php?update=success [L]

Sounds like it would be a good idea to use the URL. Something like file.php?update=success

Then:

[syntax=php]<?php
if(isset($_GET['update']) && $_GET['update'] == "success") {
echo "Updated!";
}
?>[/syntax]

Hmm...I'm not too familiar with array to string conversion errors, or arrays using this method in general. But this is what it should look like, somewhat. Do not worry about the number values in the array, just ignore those and look at all other values within brackets [syntax=php] // You should chan...

You can try changing it back to the way it was, then do print_r($images); somewhere, then source directly from the array with $images[value] Example would be: [value1] => something [value2] => something else [syntax=php] <?php echo "Value 1 is equal to ". $images['value1']; ?> [/syntax]

Cookies are user editable, so you need to first make sure you protect against sql injection with them. If you have, you then should encode or hash them in some manner so that a user will have a hard time faking them in any way.

If image_id is not set in the url you are using a string to process an array which is why you get the error. If you fix that, the image seems to show correctly as seen in: http://www.robcnossen.nl/view_album.php ... /7/122.jpg

The real problem is with the <a href> I believe you need to use a foreach for that as well

You should really add more security to those cookies. Just a suggestion

$username will return the value of true because you are using isset(); Remove that and give it a try.

You aren't selecting uid from your database in your query. You need to add that into your query, then later on add it to your returned results array.

You have a function called search_results(); as seen here:

[syntax=php]$results = search_results($keywords);[/syntax]
You undefined index notice is a result of there not being a uid being selected from within your function. You are going to have to post the function for more information.

Because the tables in the database needs to match the tables you are selecting. This error means that you were selecting from a table/column that didn't exist, therefore it couldn't complete and gave an unknown column error.

You are going to have to post the function search_results(); but that generally means that you aren't selecting it from the database so it's returning an empty result.

That error simply means the column you are trying to select from, doesn't exist. You need to create it first.

These lines have a couple things wrong with them, however the main thing is that you are putting php tags within php which will provide the error you stated. Change all this: [syntax=php] foreach($results as $result) { echo '<p> <strong>ID: </strong>', $result['ID'], '<br>',<?php echo "<a href=...

There is no error in the way you used it unless you are using the php tags within php tags like: [syntax=php] <?php some code... <?php echo "<a href='profile.php?uid=" .$result['uid']. "'>" .$result['Username']. "</a>"; ?> some code... ?>[/syntax] If you aren't, post li...

If you put that on login.php, removed the redirect on login.php, and received no errors warnings or notices, I really have no idea

Is there a reason why you can't just gather the id from the database?

[syntax=php]<?php echo "<a href='profile.php?uid=" .$result['uid']. "'>" .$result['Username']. "</a>"; ?>[/syntax]

There is no way to help without posting anything.

Where is this "valid_credentials" function it shows? You will need to query your database at some point to set their session uid from the database. It should look something like this: [syntax=php] // DO NOT forget to filter the variables with mysql_real_escape_string(); $result = mysql_que...

Put this at the top of login.php within your php tags and remove the redirect for now so it remains on the same page.

[syntax=php]error_reporting(E_ALL);
ini_set('display_errors', '1');[/syntax]

Your login page says you are redirecting users to a user.php.