content won't display

Ask about a PHP problem here.
Post Reply
Porkypie
Posts: 25
Joined: Wed Jan 02, 2013 3:52 pm
Location: Netherlands

content won't display

Post by Porkypie »

Hey!

I made this "while loop", but the content that comes after my loops won't display anymore.

Can anyone tell me why? here's the code:

[syntax=php] <?php

$result = mysql_query("SELECT `gebruikers_naam`, `achternaam`, `voornaam`, `email`, `telefoon` FROM gebruikers");
echo mysql_error();
echo "<table>
<tr>
<th style='display:none;'>id</th>
<th>Gebruikersnaam</th>
<th>voornaam</th>
<th>achternaam</th>
<th>E-mail</th>
<th>telefoon</th>
<th>wijzigen</th>
<th>Verwijderen</th>
</tr>";


while ($row = mysql_fetch_array($result)){

echo "<tr>";
echo "<td style='display:none;'>" . $row['id'] . "</td>";
echo "<td>" . $row['gebruikers_naam'] . "</td>";
echo "<td>" . $row['voornaam'] . "</td>";
echo "<td>" . $row['achternaam'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['telefoon'] . "</td>";
echo "<td> wijzig </td>";
echo "<td> <input type='button' name='verwijderen' value='verwijder' /> </td>";
echo "</tr>";
}
echo "</table>";

die();
?> [/syntax]
ExtremeGaming
Posts: 205
Joined: Mon Jul 09, 2012 11:13 pm

Re: content won't display

Post by ExtremeGaming »

Well anything after the loop is being cancelled by your call of die(); which ends the entire script.
<?php while(!$succeed = try()); ?>
Post Reply